2019 Multi-University Training Contest 1
2019-07-26 / Luo Jinrong   

进度

A B C D E F G H I J K L M

1004. Vacation

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#include<bits/stdc++.h>
#define FIN freopen("./1004.in","r",stdin)
#define debug(x) cout<<#x"=["<<x<<"]"<<endl
using namespace std;
typedef long long ll;
const ll maxn(1e5+5);
const double pi=acos(-1);
struct car{
ll l,s,v;
double t;
}c[maxn];
double ans;
ll n,sum[maxn];
int main(){
#ifndef ONLINE_JUDGE
FIN;
#endif
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
while(cin>>n){
ans=0;
sum[0]=0;
for(ll i=1;i<=n+1;i++){
cin>>c[i].l;
sum[i]=sum[i-1]+c[i].l;
}
for(ll i=1;i<=n+1;i++){
cin>>c[i].s;
c[i].s+=sum[i]-c[1].l;
}
for(ll i=1;i<=n+1;i++){
cin>>c[i].v;
c[i].t=(c[i].s+0.0)/c[i].v;
ans=max(ans,c[i].t);
}
cout<<fixed<<setprecision(10)<<ans<<endl;
}
}

1005. Path

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#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF(0x3f3f3f3f3f3f3f);
const double ESP(1e-9);
const ll mod(998244353);
#define per(i, a, b) for(int i=a; i<b; i++)
#define rep(i, a, b) for(int i=b-1; i>=a; i--)
#define mem(a, b) memset(a, b, sizeof(a))
ll powmod(ll a, ll b) { ll res = 1; a %= mod; assert(b >= 0); for (; b; b >>= 1) { if (b & 1)res = res * a%mod; a = a * a%mod; }return res; }
ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }

const int MAXN(1e4 + 7);
int T, n, m;
struct spfa {
int head1[MAXN], nxt1[2*MAXN];
int to[2*MAXN];
ll val[2*MAXN];
ll len[MAXN];
int vis[MAXN];
queue<int> Q;
int cnt1;
spfa(int n=0, int m=0) {
per(i, 1, n+1) {
head1[i]=0;
}
per(i, 1, m+1) {
nxt1[i]=0;
}
cnt1 = 1;
}
void init(int n=0, int m=0) {
per(i, 1, n+1) {
head1[i]=0;
}
per(i, 1, m+1) {
nxt1[i]=0;
}
cnt1 = 1;
}
void add(int u, int v, int w) {
nxt1[cnt1] = head1[u];
head1[u] = cnt1;
to[cnt1] = v;
val[cnt1++] = w;
}
void SPFA(int s) {
per(i, 1, n+1) {
len[i] = INF;
vis[i] = 0;
}
vis[s] = 1;
len[s] = 0;
Q.push(s);

while (!Q.empty()) {
s = Q.front();
Q.pop();
vis[s] = 0;
for(int it=head1[s]; it; it=nxt1[it]) {
if(len[to[it]]>len[s]+val[it]) {
len[to[it]]=len[s]+val[it];
if(!vis[to[it]]) {
Q.push(to[it]);
vis[to[it]] = 1;
}
}
}
}
}
}SS;

class Dinic {
public:
int N, S, T;
vector<int> head; //存每个点最后一条边
vector<int> cur; //当前弧优化,进一步加速
vector<int> depth; //存每次bfs后每个点的深度
vector<int> nxt; //存每条边的前一条边
vector<int> To; //存每条边连接的另一个点
vector<ll> Val; //存每条边的权重
ll outt; //存最大流

public:
Dinic(int Nn=0, int Ss=0, int Tt=0): N(Nn), S(Ss), T(Tt) {
head.assign(N+1, 0);
depth.resize(N+1);
Val.resize(2);
To.resize(2);
nxt.resize(2);
}
void init(int Nn=0, int Ss=0, int Tt=0) {
N=Nn, S=Ss, T=Tt;
head.assign(N+1, 0);
depth.resize(N+1);
Val.resize(2);
To.resize(2);
nxt.resize(2);
}
void _Add(int u, int v, ll w) {
nxt.push_back(head[u]);
head[u] = To.size();
To.push_back(v);
Val.push_back(w);
}
void addEdge(int u, int v, ll w) {
_Add(u, v, w);
_Add(v, u, 0);
}
int bfs() {
queue<int> qq;
qq.push(S);
vector<int> marked;
marked.assign(N+1, 0);
marked[S] = 1;
marked[T] = depth[S] = 0;
int tmp;

while(!qq.empty()) {
tmp = qq.front();
qq.pop();
for(int i=head[tmp]; i; i=nxt[i]) {
if(Val[i] && !marked[To[i]]) {
marked[To[i]] = 1;
depth[To[i]] = depth[tmp]+1;
qq.push(To[i]);
}
}
}
if(marked[T]) {
return 1;
}
return 0;
}
int dfs(int pos, ll val) {
if(pos==T) {
return val;
}
for(int& i=cur[pos]; i; i=nxt[i]) { //利用当前弧,&饮用保证当前弧能被修改
if(Val[i] && depth[To[i]]==depth[pos]+1) {
ll valu = dfs(To[i], min(val, Val[i]));
if(valu) {
Val[i] -= valu;
Val[i^1] += valu;
return valu;
}
}
}
return 0;
}
void dinic() {
outt = 0;
while(bfs()) {
cur = head; //赋值当前弧
ll val;
while((val=dfs(S, INF))) {
outt += val;
}
}
}
}DD;

int marked[MAXN];
void dfs(int pos) {
marked[pos] = 1;
for(int it=SS.head1[pos]; it; it=SS.nxt1[it]) {
if(SS.len[SS.to[it]]==SS.len[pos]+SS.val[it]) {
DD.addEdge(pos, SS.to[it], SS.val[it]);
if(!marked[SS.to[it]]) {
dfs(SS.to[it]);
}
}
}
}

int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);

cin >> T;
while(T--) {
cin >> n >> m;
SS.init(n, m);
int u, v, w;
per(i, 0, m) {
cin >> u >> v >> w;
SS.add(u, v, w);
}
SS.SPFA(1);
DD.init(n, 1, n);
per(i, 1, n+1) {
marked[i]=0;
}
dfs(1); //建网络流边
DD.dinic();
cout << DD.outt << endl;
}

return 0;
}

return 0;


本文链接:
https://luojinrong.github.io/2019/07/26/2019-Multi-University-Training-Contest-1/